UPSEE 2019 Solved Paper

The work done during the process from D to C= area of DCQP, which is in shown figure below ⇒ Area DCQP=2p×(2V−V)=2pV
Work done during B to A=− area ABQP
Where, negative sign is due to compression along BA.
⇒ area ABQP=−p×(2V−V)=−pV
Hence, the work done in the complete cycle.
=2pV−pV=pV
∴ Correct option is (a).