UPSEE 2019 Solved Paper

We have,
6x2+xy−12y2−13x+6y +6=0
Here, a=6,h=

1

2

,b=−12
g=−

13

2

f=3,c=6
∵a+b=6−12=−6≠0
∴ A pair of line is not perpendicular and ∵h2≠ab
∴ Pair of line is not parallel
Hence, pair of straight line is not passing through origin, neither parallel nor perpendicular.