UPSEE 2019 Solved Paper

A ball at a depth of 200m in a tank is shown in figure belowHere, depth h=200m and percentage decrease in volume =0.1%
As, pressure at depth h is given by
p=ρgh
where, g=9.8ms−2
and ρ=103kgm−3
So, p=103×9.8×200
⇒p=19.6×105N∕m2
Now, the bulk modulus
k=

p

ΔV V

⇒k=

19.6×105

0.1 100

=1.96×109Nm−2
Hence, the bulk modulus of the material of ball is 1.96×109Nm−2