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Question : 79 of 150
Marks:
+1,
-0
Solution:
20% ionisation of weak acid
Total moles at equilibrium
=1−α+α+α=1+α i=| Total moles |
| Initial moles |
= =1+0.2=1.2 We know that, lowering in freezing point of the solutions
(ΔTb)=iKf m =1.2×1.86Kkgmol−1×0.5 =1.116K≈1.12K
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