UPSEE 2018 Solved Paper

Relation between internal energy change (ΔE°) and enthalpy change (ΔH°) of a reaction is given by
ΔH°=ΔE°+ΔngRT ......(I)
Δng= moles of product − moles of reactant For the reaction given,
OF2(g)+H2O(g)→O2(g)+2HF(g)
Δng=(1+2)−(1+1)
Δng=1{ΔH=−310kJ,=−310000J}
Putting the values in Eq (i)
−310000J=ΔE+1(8.3141JK−1mol−1) (298K)
ΔE=−312,477.572J≈−312.5kJ