UPSEE 2018 Solved Paper

∴ Acceleration of aeroplane w.r.t. the earth,
aA→E=5m∕s2
Acceleration of stone w.r.t. the earth,
aS→E=−10m∕s2
or aE→S=−aS→E=10m∕s2
Thus, acceleration of aeroplane w.r.t. the stons,
aA→S=aA→E+aE→S =5+10=15m∕s2
∴ Relative separation between the stone and aeroplane in 2s,
s=

1

2

(aA→S)t2=

1

2

×15×(2)2=30m