UPSEE 2018 Solved Paper

Let the speed of fluid at outlet is v.
Applying Bernoulli's theorem,
p1+ρgh+

1

2

ρv2=constant
p0+ρgh+0=p0+0+

1

2

ρv2
∴ v=√2gh ......(i)
At outlet,v‌sin‌θ vertical velocity of the fluid at outlet,
v2=u2+2gh1
For maximum height,
0=(v‌sin‌θ)2−2gh1
∴ h1=

v2sin2θ

2g

=

2ghsin2θ

2g

[ { from Eq. (i) }]
=hsin2θ
h1=h‌sin2θ