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Question : 141 of 150
Marks:
+1,
-0
Solution:
We have,
=sin(10x+6y) ......(i)
Put
10x+6y=v ⇒10+6=⇒ =(−10 ) ∴ Eq. (i) becomes reduces to
(−10)=sin‌v‌ ⇒=6‌sin‌v+10 ⇒∫=∫dx ⇒‌∫ =∫dx [∵sin‌x=] ⇒
‌∫=∫dx Put
tan‌=t‌‌⇒sec2dv=dt ∴
∫=∫dx ⇒
‌∫=∫dx ⇒
tan−1()=x+C ⇒
5t+3=4‌tan(4x+k) ⇒
5‌tan‌=4‌tan(4x+k)−3 where,
k=4c ⇒
5‌tan()=4‌tan(4x+k)−3 ⇒
5‌tan(5x+3y)=4‌tan(4x+k)−3
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