Given, y=x^{2}. As x \\to2, y \\to4 what must the value of \\delta be for which from |x-2| \\in =0.001 ?

Correct Answer is : 0<δ<0.00025

UPSEE 2017 Solved Paper

Question : 122 of 150

Marks: +1, -0

Given, y=x2. As x→2,y→4 what must the value of δ be for which from |x−2|<δ it follow that |y−4|>∈=0.001?

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