UPSC NDA Math Model Paper 9

Given, Two poles are 10 m and 20 m high. AB = 10m, and CD = 20m
Also given, the line joining their tops makes an angle of 15° with the horizontal.
⇒∠CAE = 15°
CE = CD - ED = 20 - 10
⇒ CE = 10m
In triangle ACE, we have
tan‌15°=

CE

AE

⇒AE=

CE

tan‌15°

⇒AE=

10

2−√3

⇒AE=37.3m
Hence, Two poles are 10 m and 20 m high. The line joining their tops makes an angle of 15° with the horizontal, the approximate distance between the poles 37.3 m