UPSC NDA Math Model Paper 9

Given P(A) = 0.6 and P(B) = 0.2
P(A ∩ B) = P(A) × P(B)
⇒ P(A ∩ B) = 0.6 × 0.2 = 0.12
P(A ∪ B) = P(A) + P(B) - P(A ∩ B)
⇒ P(A ∪ B) = 0.6 + 0.2 - 0.12
⇒ P(A ∪ B) = 0.68
P((A ∪ B)') = 1 - P(A ∪ B)
⇒ P((A ∪ B)') = 1 - 0.68
⇒ P((A ∪ B)') = 0.32