UPSC NDA Math Model Paper 9

Given f(x)‌=‌2x3−3x2−12x+6
As we know that Point c from the domain of the function y = f(x) is called stationary point of the function y =f(x)‌if‌f′(c)=0
First find f′(x).
f′(x)=‌6x2−‌6x−12
Now,
f’(x)=0
⇒6x2−6x−12=0
⇒(x−2)(x+1)=0
⇒ x = 2 and x = - 1
∴ Stationary point of the function are 2 and -1