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Question : 91 of 120
Marks:
+1,
-0
Solution:
Here we have to find the value of
∫dx Let
x2=t ⇒= Let
=+ ⇒ t = A (t + 3) + B (t + 2)
By putting t = - 2 on both the sides of (1) we get A = - 2
By putting t = - 3 on both the sides of (1) we get B = 3
=+ By substituting
x2=t in the above equation we get
⇒=+ ⇒∫dx =−2‌∫+3‌∫ As we know that,
∫=tan−1()+C where
C is a constant
⇒∫dx =tan−1() +tan−1()+C =−√2tan−1()+√3tan−1()+C Where
C is a constant
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