UPSC NDA Math Model Paper 8

Here, radius = 6 and centre at (3, 5)
∴Equation of circle = (x−3)2+(y−5)2=62 ⇒(x−3)2+(y−5)2=36
Now check the points,
1. (-2, -1):
⇒(−2−3)2+(−1−5)2=25+36>36
So, this point lies outside of circle.
2.(0, 1):
⇒(0−3)2+(1−5)2=9+16<36
So, point (0,1) lies inside the circle
Hence, option (2) is correct.