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Question : 38 of 120
Marks:
+1,
-0
Solution:
[√4x2+x−3−2x] this is ∞ - ∞ form
Here we rationalize numerator
[√4x2+x−3−2x] ×| √4x2+x−3+2x |
| √4x2+x−3+2x |
| [(√4x2+x−3)2−(2x)2] |
| √4x2+x−3+2x |
| [4x2+x−3−4x2] |
| √4x2+x−3+2x |
, this is
∞∕∞ form
Here we divide the numerator and denominator by x
= Hence, option 3 is the correct answer.
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