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Question : 87 of 120
Marks:
+1,
-0
Solution:
Given,
=− and
=−− Consider,
(×)+=0 Multiply by
on both side, we have
⇒×[(×)+]=0 ⇒×[(×)]+(×)=0 ⇒(.)−(.)+(×)=0 .... (1)
Given
.=3,.=2 and
×=−2−− Equation 1!) becomes,
⇒3−2+(−2−−)=0 ⇒2=3+(−2−−) ⇒2=3(−)+(−2−−) ⇒=−+−2 Hence, if
=− and
=−−. Then the vector
satisfying
(×)+=0 and
.=3, is
=−+−2
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