Determine {f}({x}) for {f'}({x})=4 {x}^{3}-2 {1}/\sqrt{{x}}+{e}^{-4 {x}}, and {f}(0)=\frac{3}{4}

Correct Answer is : x4−4√x−e−4x4+1

x^{4}-4 \\sqrt{x}-{e^{-4 x}}/{4}+1

x^{4}-4 \\sqrt{x}+{e^{-4 x}}/{4}+1

x^{4}-\\sqrt{x}-{e^{-4 x}}/{4}+1

UPSC NDA Math Model Paper 7

Question : 83 of 120

Marks: +1, -0

Determine f(x) for f′(x)=4x3−2

√x

+e−4x, and f(0)=

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