UPSC NDA Math Model Paper 7

Here, cos‌θ1+cos‌θ2+cos‌θ3+cos‌θ4 +cos‌θ5=5
Since, the maximum value of cos θ = 1
We have five terms in LHS of the given equation. Every term should be = 1
cos‌θ1=cos‌θ2=cos‌θ3=cos‌θ4 =cos‌θ5=1
∴θ1=θ2=θ3=θ4=θ5=0°
Now, sin‌θ1+sin‌θ2+sin‌θ3
=3×(sin‌0°)
=0
Hence, option (1) is correct.