UPSC NDA Math Model Paper 7

Here, a straight line passes through the points (5, 0) and (0, 3)
∴ Slope =

3−0

0−5

=

−3

5

So, equation of line:
y−0=−3∕5(x−5) ⇒3x+5y−15=0
Now, distance of point (4,4) from a line 3x+5y−15=0
=|

3(4)+5(4)−15

√32+52

|=

17

√34

=

√17×√17

√17×√2

=√

17

2

Hence, option (2) is correct.