Given lines are x - 2y = 1 and x + 3y = 2 x - 2y = 1 .... (1) x + 3y = 2 ..... (2) equation (2) - equation (1), we get ⇒ (x + 3y) - (x - 2y) = 2 - 1 ⇒ 5y = 1 ∴ y = 1/5 Put the value of y in equation (1), we get x = 7/5 Point of intersection: (x,y)=(x1,y1)=(
7
5
,
1
5
) Let slope of the straight line 3x+2y=0 is m1, So, slope =m1=
−3
2
We know that when two lines are parallel, then their slopes will be equal. ∴ slope =m=m1=
−3
2
Now equation of the line is y−y1=m(x−x1) ⇒(y−