Which of the following is equal to {{{\tan}} ^{ - 1}}( {{{8{{x}}\\sqrt{{x} }}/{{1 - 16{{{x}}^3}}}} ).

Correct Answer is : 2tan−1(4x√x)

2{{{\tan}} ^{ - 1}}( {4{{x}}\\sqrt{{x} } )

{{{\tan}} ^{ - 1}}( {8{{x}}\\sqrt{{x} } )

{{{\tan}} ^{ - 1}}( {4{{x}}\\sqrt{{x} } )

UPSC NDA Math Model Paper 6

Question : 79 of 120

Marks: +1, -0

Which of the following is equal to tan−1(

8x√x

1−16x3

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