UPSC NDA Math Model Paper 6

We have to find the distance of the point (2, 1, 0) from the plane 2x + y + 2z + 5 = 0
As we know that, the distance between the point and the plane is given by |

Ax1+By1+Cz1−d

√A2+B2+C2

|
Here, x1=2,y1=1 and z1=0
So, the distance of the given point form the given plane = =|

2×2+1×1+2×0+5

√22+(1)2+(2)2

|
=|

10

√9

|
So, the distance between the plane and the point is 10/3 units
Hence, option C is the correct answer.