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Question : 62 of 120
Marks:
+1,
-0
Solution:
Here, we have two vectors
=−2+3 and
=3−2+. ⇒||=√12+(−2)2+32=√14 and
||=√32+(−2)2+(1)2=√14 ⇒.=(−2+3).(3−2+) =3+4+3=10 By, substituting the values of
||,|| and
. in
cosθ=, we get
⇒cosθ== ⇒θ=cos−1() Hence, option
B is the correct answer.
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