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Question : 54 of 120
Marks:
+1,
-0
Solution:
We know that
The lines
== and
== are coplanar then
⇒|| x2−x1 | y2−y1 | z2−z1 |
| a1 | b1 | c1 |
| a2 | b2 | c2 |
| =0 Given The lines
== and
== are coplanar
Here,
x1=1,x2=2,y1=4,y2=3,z1=5,z2=4, a1=k,b1=2,c1=1 a2=1,b2=1,c2=−k ⇒||=0 ⇒1(−2k−1)+1(−k2−1)−1(k−2)=0 ⇒−2k−1−k2−1−k+2=0 ⇒−k2−3k=0 ⇒k(k+3)=0 Neglect
k=0 ⇒k=−3 Hence, The lines
== and
== are coplanar if the value of k = - 3
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