UPSC NDA Math Model Paper 5

Given: Equation of hyperbola

x2

36

−

y2

64

=1
As we know that, equation of a horizontal hyperbola is given by

x2

a2

−

y2

b2

=1
So, by comparing the given equation of hyperbola with

x2

a2

−

y2

b2

=1 we get,
⇒a2=36 and b2=64
As we know that, latus rectum of an horizontal hyperbola is given by

2b2

a

So, by substituting b2=64 and a=6 in

2b2

a

we get
⇒

2.64

6

=

64

3

units
Hence, option C is the correct answer.