Given: Equation of lines is 4x – 3y + 6 = 0 The given equation can be re-written as: y=
4
3
.x+2 By comparing the above equation with y = m ⋅ x + c we get slope of the given line m1=
4
3
Option A: 3x+4y−7=0 If equation of the normal is 3x + 4y - 7 = 0 and this equation can be re-written as: y=−
3
4
.x+
7
4
By comparing the above equation with y = m ⋅ x + c we get slope of the normal m2=−
3
4
∵ The line and normal are perpendicular to each other so the product of their slopes should be - 1. ⇒m1.m2=4∕3.(−3∕4)=−1 So, option A represents the equation of the normal to the given. Hence, option A is the correct answer.