UPSC NDA Math Model Paper 4

Here, A, B, C are in AP, so 2B = A + C = 30 + C .....(1)
ABC is a triangle, so A + B + C =180° ⇒ B = 150 - C .....(2)
Add (1) and (2), we get
3B = 180 ⇒ B = 60°
So, C = 90°
2sinA + 3tanB - 4cosC = 2(sin 30) + 3 tan (60) - 4 cos 90
=2(1∕2)+3√3
=1+3√3
Hence, option (4) is correct.