\\intx^{3} \sin 3 x d x=

Correct Answer is : −x3cos3x3+x2sin3x3+2xcos3x9 −2sin3x27+C

-{x^{3} \cos 3 x}/{3}-{x^{2} \sin 3 x}/{3}+\frac{2 x \cos 3 x}{9} -\frac{2 \sin 3 x}{27}+C

{x^{3} \cos 3 x}/{3}+{x^{2} \sin 3 x}/{3}+\frac{2 x \cos 3 x}{9} -\frac{2 \sin 3 x}{27}+C

-{x^{3} \cos 3 x}/{3}+{x^{2} \sin 3 x}/{3}+\frac{2 x \cos 3 x}{9} -\frac{2 \sin 3 x}{27}+C

-{x^{3} \cos 3 x}/{3}+{x^{2} \sin 3 x}/{3}-\frac{2 x \cos 3 x}{9} -\frac{2 \sin 3 x}{27}+C

UPSC NDA Math Model Paper 2

Question : 98 of 120

Marks: +1, -0

∫x3‌sin‌3‌x‌d‌x=

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