UPSC NDA Math Model Paper 10

Given line 3x - 2y = 4
⇒y=

3

2

x+2
⇒ Slope (m1)=

3

2

and c1=2
Now for the slope of parallel line (m2)
m1=m2=

3

2

Parallel line has the slope

3

2

and passes through (1,5)
∴ Equation of the parallel line is (y−y1)=m(x−x1)
⇒y−5=

3

2

(x−1)
⇒3x−2y+7=0