Find the angle between the line \frac{x-1}{3}=\frac{y+1}{-1}=\frac{z-3}{2} and the plane 3 {x}+4 {y}+{z}+5=0

Correct Answer is : sin−1(√752)

\sin ^{-1}(\\sqrt{\frac{7}{52}})

\cos ^{-1}(\\sqrt{\frac{7}{52}})

\sin ^{-1}(\\sqrt{\frac{5}{52}})

\cos ^{-1}(\\sqrt{\frac{5}{52}})

UPSC NDA Math Model Paper 10

Question : 104 of 120

Marks: +1, -0

Find the angle between the line

x−1

y+1

−1

z−3

and the plane 3x+4y+z+5=0

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