The center and the radius of the sphere |2 \overrightarrow{{r}}+(3 \overrightarrow{{i}}-\overrightarrow{{j}}+4 \overrightarrow{{k}})|=4 are:

Correct Answer is : center =(−32,12,−2) and radius =2.

center =(\frac{3}{2}, \frac{-1}{2}, 2) and radius =2.

center =(\frac{-3}{2}, \frac{ 1}{2}, -2) and radius =2.

center =(\frac{3}{2}, \frac{-1}{2}, 2) and radius =1.

center =(\frac{-3}{2}, \frac{-1}{2}, 2) and radius =1.

UPSC NDA Math Model Paper 1

Question : 83 of 120

Marks: +1, -0

The center and the radius of the sphere |2

→

+(3

→

−

→

)|=4 are:

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