UPSC NDA Math Model Paper 1

Here, we have to find the decimal equivalent of the binary number 11001.011
⇒2−3×1+2−2×1+2−1×0+20 ×1+21×0+22×0+23×1+24×1
=0.125+0.25+0+1+0+0 +8+16=25.375
So, the decimal equivalent of the binary number 11001.011 is (25.375)10
Hence, option A is the correct answer.