UPSC NDA II 2023 Mathematics Solved Paper

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Consider the following for the next three (03) items that follow :
Let (1+x)n=1+T1x+T2x2+T3x3+...+Tnxn.
[NDA II 2023]
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Question : 39 of 120
 
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What is 1−T1+2T2−3T3+...+(−1)nnTn equal to?
[NDA II 2023]
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