UPSC NDA II 2018 Mathematics Solved Paper

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Question : 38 of 120

Marks: +1, -0

If A+B+C=180°, then what is sin‌2‌A‌–‌sin‌2‌B‌–‌sin‌2‌C equal to?

[NDA II 2018]

–4 sin A sin B sin C
–4 cos A sin B cos C
–4 cos A cos B sin C
–4 sin A cos B cos C

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