What is the adjoint of the matrix (\table \cos(-\theta),-\sin(-\theta);-\sin(-\theta),\cos(-\theta)) ? [NDA II 2018]

Correct Answer is : (cosθ−sinθ−sinθcosθ)

(\table \cos\theta,-\sin\theta;-\sin\theta,\cos\theta)

(\table \cos\theta,\sin\theta;\sin\theta,\cos\theta)

(\table \cos\theta,\sin\theta;-\sin\theta,\cos\theta)

(\table \cos\theta,-\sin\theta;\sin\theta,\cos\theta)

UPSC NDA II 2018 Mathematics Solved Paper

Question : 14 of 120

Marks: +1, -0

What is the adjoint of the matrix (

cos(−θ)	−sin(−θ)
−sin(−θ)	cos(−θ)

) ?

[NDA II 2018]

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cos‌θ	−sin‌θ
−sin‌θ	cos‌θ

cos‌θ	sin‌θ
sin‌θ	cos‌θ

cos‌θ	sin‌θ
−sin‌θ	cos‌θ

cos‌θ	−sin‌θ
sin‌θ	cos‌θ