UPSC NDA II 2018 General Ability Solved Paper

CONCEPT:
- Ohm's law: At constant temperature, the potential difference across a current carrying wire is directly proportional to current flowing through it.
- V=IR
Where V is the potential difference, R is resistance and I iscurrent.
EXPLANATION:
We have graph between Current (I) and potential difference (V):
As V=IR
So I=V∕R
The above relation of I and R is a straight line equation in which 1∕R gives the slope of the line.
Slopeof graph =1∕R
From the given graph in the question, as slope of graph 1 is maximum and then it is of graph 3 and slope of graph 2 is minimum.
∴ Slope of graph 1> slope of graph 3> slope of graph 2
So 1∕R1>1∕R3>1∕R2
Hence R2>R3>R1