A force F^{\to} acting on an electric charge q, in presence of an electromagnetic field, moves the charge parallel to the magnetic field with velocity v^{\to} . The F^{\to} is equal to (where E^{\to} and B^{\to} are electric field and magnetic field respectively) [NDA II 2014]

UPSC NDA II 2014 General Ability Paper

Question : 68 of 150

Marks: +1, -0

A force

→

acting on an electric charge q, in presence of an electromagnetic field, moves the charge parallel to the magnetic field with velocity

→

. The

→

is equal to (where

→

and

→

are electric field and magnetic field respectively)

[NDA II 2014]

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