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Question : 24 of 120
Marks:
+1,
-0
Solution:
⋅×Now,
×=||=(1+x−y−x+x2)−(x+x2−xy−y+xy.+(x2−y.=(1−y+x2)−(x+x2−y)+(x2−y)Now
.(×)=(−){(1−y+x2)−(x+x2−y)+(x2−y)}=1−y+x2−(x2−y)=1−y+x2−x2+y=1
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