What is the equation to the straight line passing through the point (- \sin \theta, \cos \theta) and perpendicular to the line x \cos \theta+y \sin \theta=9 ?

Correct Answer is : xsinθ−ycosθ+1=0

x \sin \theta-y \cos \theta-1=0

x \sin \theta-y \cos \theta+1=0

x \cos \theta-y \sin \theta+1=0

UPSC NDA I 2024 Mathematics Paper

Question : 59 of 120

Marks: +1, -0

What is the equation to the straight line passing through the point (−sin‌θ,cos‌θ) and perpendicular to the line x‌cos‌θ+ysin‌θ=9 ?

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