The solution of the differential equation \frac{\dy}{\dx} =cos | y−x |+1 is [NDA I 2019]

Correct Answer is : ex [sec ( y−x )−tan ( y−x )]=c

e^\x [sec ( y−x )−tan ( y−x )]=c

e^\x [sec ( y−x )+tan ( y−x )]=c

e^\x [sec ( y−x )tan ( y−x )]=c

e^\x =[csec ( y−x )tan ( y−x )]

UPSC NDA I 2019 Mathematics Solved Paper

Question : 66 of 120

Marks: +1, -0

The solution of the differential equation

=cos | y−x |+1 is

[NDA I 2019]

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