If the difference between the roots of the equation x^{2}+kx+1=0 is strictly less than \sqrt5 where |k| \geq 2 then k can be any element of the interval [NDA I 2017]

Correct Answer is : (−3,−2]∪[2,3)

UPSC NDA I 2017 Mathematics Solved Paper

Question : 34 of 120

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If the difference between the roots of the equation x2+kx+1=0 is strictly less than √5 where |k|≥2 then k can be any element of the interval

[NDA I 2017]

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