What is the equation of the ellipse having foci (\pm2,0) and the eccentricity 1/4 ? [NDA I 2017]

Correct Answer is : x264+y260=1

\frac{x^{2}}{64}+ \frac{y^{2}}{60}=1

\frac{x^{2}}{60}+ \frac{y^{2}}{64}=1

\frac{x^{2}}{20}+ \frac{y^{2}}{24}=1

\frac{x^{2}}{24}+ \frac{y^{2}}{20}=1

UPSC NDA I 2017 Mathematics Solved Paper

Question : 27 of 120

Marks: +1, -0

What is the equation of the ellipse having foci (±2,0) and the eccentricity

[NDA I 2017]

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