UPSC NDA I 2015 Mathematics Solved Paper

It is given that the required line is perpendicular to the given line.Hence the slope of the required line will be the negative reciprocal of the slope of the given line.
3x+y=3
⇒y=−3x+3
m=−3
So Slope of the required line m′=

1

3

Hence ,equation of the line is

y−2

x−2

=

1

3

3y−6=x−2
3y−x=4
⇒

y

4/3

+

x

−4

=1(intercept form)
Therefore the y-intercept will be
yintercept=

4

3