If 1,\omega,\omega^2 are the cube roots of unity, then the value of (1+\omega)(1+\omega^2)(1+\omega^4)(1+\omega^8) is [NDA I 2015]

UPSC NDA I 2015 Mathematics Solved Paper

Question : 13 of 120

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If 1,ω,ω2 are the cube roots of unity, then the value of
(1+ω)(1+ω2)(1+ω4)(1+ω8) is

[NDA I 2015]

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