UPSC NDA I 2015 Mathematics Solved Paper

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Question : 10 of 120

Marks: +1, -0

If z=

−2(1+2i)

3+i

Where i=√−1,then the argument θ(−π<θ≤π) of z is

[NDA I 2015]

3π
4
π
4
5π
6
−
3π
4

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