The angle of elevation of a tower at a level ground is 30^{\circ}. The angle of elevation becomes \theta when moved 10 {\m} towards the tower. If the height of tower is 5 \sqrt{3} {\m}, then what is \theta equal to?

UPSC NDA I 2012 Mathematics Paper

Question : 35 of 120

Marks: +1, -0

The angle of elevation of a tower at a level ground is 30∘. The angle of elevation becomes θ when moved 10 m towards the tower. If the height of tower is 5√3m, then what is θ equal to?

45∘
60∘
75∘
None of the above

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