UPSC NDA 2 2022 Mathematics Solved Paper

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Question : 82 of 120

Marks: +1, -0

If f(α)=√sec2α−1, then what is ‌

f(α)+f(β)

1−f(α)f(β)

equal to?

[NDA II 2022]

f(α−β)
f(α+β)
f(α)f(β)
f(αβ)

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