If 1+2(\sin x+\cos x)(\sin x-\cos x)=0 where 0< x< 360^{\circ}, then how many values does x take ? [NDA II 2022]

Correct Answer is : Four values

UPSC NDA 2 2022 Mathematics Solved Paper

Question : 55 of 120

Marks: +1, -0

If 1+2(sin‌x+cos‌x)(sin‌x−cos‌x)=0 where 0<x<360∘, then how many values does x take ?

[NDA II 2022]

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