UPSC NDA 2 2021 Mathematics Solved Paper

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Question : 97 of 120

Marks: +1, -0

If

0

∫

−2

f(x)dx=k, then

0

∫

−2

|f(x)|dx is

[NDA-II 2021]

less than k
greater than k
less than or equal to k
greater than or equal to k

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