If A=[\table1,-1;-1,1] then the expression A^3–2A^2 is: [NDA II 2019]

Correct Answer is : a null matrix

UPSC NDA 2 2019 Mathematics Solved Paper

Question : 14 of 120

Marks: +1, -0

If A=[

1	−1
−1	1

] then the expression A3–2A2 is:

[NDA II 2019]

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1+1	−1−1
−1−1	1+1

1+1	−1−1
−1−1	1+1

2	−2
−2	2